-0.2x^2+2.4x+2=0

Solution for -0.2x^2+2.4x+2=0 equation:

-0.2x^2+2.4x+2=0

a = -0.2; b = 2.4; c = +2;
Δ = b2-4ac
Δ = 2.42-4·(-0.2)·2
Δ = 7.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.4)-\sqrt{7.36}}{2*-0.2}=\frac{-2.4-\sqrt{7.36}}{-0.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.4)+\sqrt{7.36}}{2*-0.2}=\frac{-2.4+\sqrt{7.36}}{-0.4}
$